Maths Permutations & Combination Definition of Permutation, Number of Permutations With or Without Repetition, Conditional Permutations Single Correct MCQ
Published on: August 13, 2026

Total number of four digit odd numbers that can be formed using 0, 1, 2, 3, 5, 7 are

A
216
B
375
C
400
D
720

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
D

0, 1, 2, 3, 5, 7 : Six digits

The last place can be filled in by 1, 3, 5, 7. i.e. , 4 ways as the number is to be odd. We have to fill in the remaining 3 places of the 4 digit number i.e. I, II, III place. Since repetition is allowed each place can be filled in 6 ways. Hence the 3 place can be filled in 6 × 6 × 6 = 216 ways.

But in case of 0 = 216 – 36 = 180 ways.

Hence by fundamental theorem, the total number will be = 180 × 4 = 720.

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.